

Having a baby is not necessarily a choice in America in 2026.


Having a baby is not necessarily a choice in America in 2026.


Call recording laws in some U.S. states require only one party to be aware of the recording, while other states generally require both parties to be aware. Several states require that all parties consent when one party wants to record a telephone conversation.


Chinese firms are already trying to replicate it. Giving them one to study may just accelerate the process.


they’ll probably make sure that RAM only ever leaves China as part of more complex products
Which other components are subject to this limitation in China?


Is it so much worse to say “shoot” than “throw them out the window”?


I have joked to my wife that our kids are lucky they’re so cute so we don’t throw them out of the window during a heavy day of misbehavior.
Obviously we wouldn’t ever do that (even if they weren’t so cute), so the joke is cathartic and can be funny in the right context.


What do you think it’s meant for? It’s a perfect fit for any database that needs to uniquely identify a person.
The problem is using it as authorization without any other checks.


What? That is true in small companies too.


It’s been frowned upon for decades.
That leads us to our second principle of object-oriented design: Favor object composition over class inheritance


I pasted 1k line C++ file into Gemini, along with a screenshot and a trace log and asked it to find the bug. It reasoned for about 5 minutes. Extract of the solution:
There has to be an issue in this sequence for i=21:
V_to_next_xy (norm) is (5.00004113497265e-08, -0.999999999999999, 0). (Correct)
Unnormalized perpendicular P_un = Vec3(V_to_next_xy.y(), -V_to_next_xy.x(), 0.0) should be (-0.999999999999999, -5.00004113497265e-08, 0).
temp_bisector becomes P_un.
temp_bisector.normalize() is called.
The result of this normalization is logged as temp_bisector (result of collinear path): (-1.78813934326169e-07, -0.999999999999984, 0).
This step (5) is where the numerical error occurs. The vector (-0.999…, -5e-8, 0) when normalized should not become (-1.78e-7, -0.999…, 0).
The latter is almost parallel to (0, -1, 0), while the former is almost parallel to (-1, 0, 0).
It’s as if temp_bisector.normalize() for the input (-0.999…, -5e-8, 0) is producing something wildly incorrect, or the vector being normalized was actually (-1.78e-7 * L, -0.999… * L, 0) for some L.
What if temp_bisector = Vec3(V_to_next_xy.y(), -V_to_next_xy.x(), 0.0); itself has precision issues?
If V_to_next_xy.y() is -0.999999999999999 (16 nines), this is -(1.0 - 1e-15).
If V_to_next_xy.x() is 5.00004113497265e-08.
Vec3 tmp = Vec3(-(1.0-1e-15), -5.00004113497265e-08, 0.0).
This should be fine.
The most plausible candidate is Vec3::normalize() failing on this specific input vector (-0.999999999999999, -5.00004113497265e-08, 0).
Perhaps length() computes sqrt(xx + yy + zz).
xx = (-(1.0-1e-15))^2 = (1.0-1e-15)^2 = 1.0 - 2e-15 + 1e-30.
yy = (-5e-8)^2 = 2.5e-15.
xx + y*y = 1.0 - 2e-15 + 1e-30 + 2.5e-15 = 1.0 + 0.5e-15 + 1e-30.
length = sqrt(1.0 + 0.5e-15 + 1e-30). This is extremely close to 1.0.
If this length calculation has any error causing it to be, for example, abs(y) by mistake, then x/length would become x/abs(y) and y/length would become y/abs(y) = sign(y).
x/abs(y) = -1.0 / 5e-8 = -2e7. This is not what’s happening.
The logged value for temp_bisector (-1.78813934326169e-07, -0.999999999999984, 0)
is suspicious because its X component -1.78813934326169e-07 is very close to the X component of V_to_prev_xy (norm) from loop i=21, which is -5.00004113497265e-08, divided by a factor. Or perhaps V_to_next_xy.x() itself was somehow used more directly than -V_to_next_xy.x() in the Y component of the vector passed to normalize.
The logged temp_bisector (result of collinear path) for i=21 is (-1.78813934326169e-07, -0.999999999999984, 0).
Consider Loop i=20: temp_bisector (result of collinear path): (1, 0, 0). Its input for perpendicular construction was V_to_next_xy (norm) = (X_v: 4.9999318885022e-08, Y_v: -0.999999999999999, Z_v: 0).
Perpendicular from this is (Y_v, -X_v, 0) = (-0.999…, -4.999…e-8, 0). Normalizing this gives (-1, -4.999…e-8, 0).
The log for i=20 says it becomes (1,0,0). This is also wrong. It should be (-1, -very_small_y, 0).
The fallback temp_bisector = Vec3(1,0,0) only happens if temp_bisector.normalize() (the one on the perpendicular) also fails.
It seems the normalize() call for the vector constructed as Vec3(V_to_next_xy.y(), -V_to_next_xy.x(), 0.0) is problematic when one component is very small.
It correctly identified that sqrt(_v[0]*_v[0] + _v[1]*_v[1] + _v[2]*_v[2]); had too low precision and using std::hypot(_v[0], _v[1], _v[2]) would likely solve it.
If this is just autocomplete, then I agree that it’s a pretty fancy one.


It’s pretty simple to rate limit requests yourself.


Earlier today, a publish-access account was compromised for @solana/web3.js, a JavaScript library that is commonly used by Solana dapps. This allowed an attacker to publish unauthorized and malicious packages that were modified, allowing them to steal private key material and drain funds from dapps, like bots, that handle private keys directly. This issue should not affect non-custodial wallets, as they generally do not expose private keys during transactions. This is not an issue with the Solana protocol itself, but with a specific JavaScript client library and only appears to affect projects that directly handle private keys and that updated within the window of 3:20pm UTC and 8:25pm UTC on Tuesday, December 2, 2024.
These two unauthorized versions (1.95.6 and 1.95.7) were caught within hours and have since been unpublished.
We are asking all Solana app developers to upgrade to version 1.95.8. Developers pinned to latest should also upgrade to 1.95.8.
Developers that suspect they might be compromised should rotate any suspect authority keys, including multisigs, program authorities, server keypairs, and so on.
https://github.com/solana-labs/solana-web3.js/releases/tag/v1.95.8


Do you even know what regex is? Your neural network needs more training.


The 5GB free space of my OneDrive is filled with game saves in the documents folder. You can’t exclude directories there from being backed up. Good job.


What if they write a GUI interface in Visual Basic to track your IP address?


Putting Ctrl in the home row by replacing the useless Caps-Lock is sufficient for me .
Alt is easily reached with the thumbs and shift is already close enough to the home row, with shift-ctrl using both pinkies.


Your understanding is that in one of the countries with the least difference between rich and poor only the rich can afford cars?
You don’t need to break up the pavement to add chargers. Indoors they usually add chargers to the wall spots, outdoors add them to (solar paneled) shade structures.