Day 11: Plutonian Pebbles

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FAQ

    • SteveDinn@lemmy.ca
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      7 months ago

      I had a very similar take on this problem, but I was not caching the results of a blink for a single stone, like youre doing with subtree_pointers. I tried adding that to my solution, but it didn’t make an appreciable difference. I think that caching the lengths is really the only thing that matters.

      C#

          static object Solve(Input i, int numBlinks)
          {
              // This is a cache of the tuples of (stoneValue, blinks) to
              // the calculated count of their child stones.
              var lengthCache = new Dictionary<(long, int), long>();
              return i.InitialStones
                  .Sum(stone => CalculateUltimateLength(stone, numBlinks, lengthCache));
          }
      
          static long CalculateUltimateLength(
              long stone,
              int numBlinks,
              IDictionary<(long, int), long> lengthCache)
          {
              if (numBlinks == 0) return 1;
              
              if (lengthCache.TryGetValue((stone, numBlinks), out var length)) return length;
      
              length = Blink(stone)
                  .Sum(next => CalculateUltimateLength(next, numBlinks - 1, lengthCache));
              lengthCache[(stone, numBlinks)] = length;
              return length;
          }
      
          static long[] Blink(long stone)
          {
              if (stone == 0) return [1];
      
              var stoneText = stone.ToString();
              if (stoneText.Length % 2 == 0)
              {
                  var halfLength = stoneText.Length / 2;
                  return
                  [
                      long.Parse(stoneText.Substring(0, halfLength)),
                      long.Parse(stoneText.Substring(halfLength)),
                  ];
              }
      
              return [stone * 2024];
          }